3.3.86 \(\int \frac {x (1-c^2 x^2)^{5/2}}{a+b \text {arccosh}(c x)} \, dx\) [286]

3.3.86.1 Optimal result

Integrand size = 26, antiderivative size = 397 \[ \int \frac {x \left (1-c^2 x^2\right )^{5/2}}{a+b \text {arccosh}(c x)} \, dx=-\frac {5 \sqrt {1-c x} \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a+b \text {arccosh}(c x)}{b}\right )}{64 b c^2 \sqrt {-1+c x}}+\frac {9 \sqrt {1-c x} \cosh \left (\frac {3 a}{b}\right ) \text {Chi}\left (\frac {3 (a+b \text {arccosh}(c x))}{b}\right )}{64 b c^2 \sqrt {-1+c x}}-\frac {5 \sqrt {1-c x} \cosh \left (\frac {5 a}{b}\right ) \text {Chi}\left (\frac {5 (a+b \text {arccosh}(c x))}{b}\right )}{64 b c^2 \sqrt {-1+c x}}+\frac {\sqrt {1-c x} \cosh \left (\frac {7 a}{b}\right ) \text {Chi}\left (\frac {7 (a+b \text {arccosh}(c x))}{b}\right )}{64 b c^2 \sqrt {-1+c x}}+\frac {5 \sqrt {1-c x} \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a+b \text {arccosh}(c x)}{b}\right )}{64 b c^2 \sqrt {-1+c x}}-\frac {9 \sqrt {1-c x} \sinh \left (\frac {3 a}{b}\right ) \text {Shi}\left (\frac {3 (a+b \text {arccosh}(c x))}{b}\right )}{64 b c^2 \sqrt {-1+c x}}+\frac {5 \sqrt {1-c x} \sinh \left (\frac {5 a}{b}\right ) \text {Shi}\left (\frac {5 (a+b \text {arccosh}(c x))}{b}\right )}{64 b c^2 \sqrt {-1+c x}}-\frac {\sqrt {1-c x} \sinh \left (\frac {7 a}{b}\right ) \text {Shi}\left (\frac {7 (a+b \text {arccosh}(c x))}{b}\right )}{64 b c^2 \sqrt {-1+c x}} \]

output

-5/64*Chi((a+b*arccosh(c*x))/b)*cosh(a/b)*(-c*x+1)^(1/2)/b/c^2/(c*x-1)^(1/ 
2)+9/64*Chi(3*(a+b*arccosh(c*x))/b)*cosh(3*a/b)*(-c*x+1)^(1/2)/b/c^2/(c*x- 
1)^(1/2)-5/64*Chi(5*(a+b*arccosh(c*x))/b)*cosh(5*a/b)*(-c*x+1)^(1/2)/b/c^2 
/(c*x-1)^(1/2)+1/64*Chi(7*(a+b*arccosh(c*x))/b)*cosh(7*a/b)*(-c*x+1)^(1/2) 
/b/c^2/(c*x-1)^(1/2)+5/64*Shi((a+b*arccosh(c*x))/b)*sinh(a/b)*(-c*x+1)^(1/ 
2)/b/c^2/(c*x-1)^(1/2)-9/64*Shi(3*(a+b*arccosh(c*x))/b)*sinh(3*a/b)*(-c*x+ 
1)^(1/2)/b/c^2/(c*x-1)^(1/2)+5/64*Shi(5*(a+b*arccosh(c*x))/b)*sinh(5*a/b)* 
(-c*x+1)^(1/2)/b/c^2/(c*x-1)^(1/2)-1/64*Shi(7*(a+b*arccosh(c*x))/b)*sinh(7 
*a/b)*(-c*x+1)^(1/2)/b/c^2/(c*x-1)^(1/2)
 

3.3.86.2 Mathematica [A] (warning: unable to verify)

Time = 0.98 (sec) , antiderivative size = 216, normalized size of antiderivative = 0.54 \[ \int \frac {x \left (1-c^2 x^2\right )^{5/2}}{a+b \text {arccosh}(c x)} \, dx=\frac {\sqrt {1-c^2 x^2} \left (-5 \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arccosh}(c x)\right )+9 \cosh \left (\frac {3 a}{b}\right ) \text {Chi}\left (3 \left (\frac {a}{b}+\text {arccosh}(c x)\right )\right )-5 \cosh \left (\frac {5 a}{b}\right ) \text {Chi}\left (5 \left (\frac {a}{b}+\text {arccosh}(c x)\right )\right )+\cosh \left (\frac {7 a}{b}\right ) \text {Chi}\left (7 \left (\frac {a}{b}+\text {arccosh}(c x)\right )\right )+5 \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arccosh}(c x)\right )-9 \sinh \left (\frac {3 a}{b}\right ) \text {Shi}\left (3 \left (\frac {a}{b}+\text {arccosh}(c x)\right )\right )+5 \sinh \left (\frac {5 a}{b}\right ) \text {Shi}\left (5 \left (\frac {a}{b}+\text {arccosh}(c x)\right )\right )-\sinh \left (\frac {7 a}{b}\right ) \text {Shi}\left (7 \left (\frac {a}{b}+\text {arccosh}(c x)\right )\right )\right )}{64 c^2 \sqrt {\frac {-1+c x}{1+c x}} (b+b c x)} \]

input

Integrate[(x*(1 - c^2*x^2)^(5/2))/(a + b*ArcCosh[c*x]),x]
 

output

(Sqrt[1 - c^2*x^2]*(-5*Cosh[a/b]*CoshIntegral[a/b + ArcCosh[c*x]] + 9*Cosh 
[(3*a)/b]*CoshIntegral[3*(a/b + ArcCosh[c*x])] - 5*Cosh[(5*a)/b]*CoshInteg 
ral[5*(a/b + ArcCosh[c*x])] + Cosh[(7*a)/b]*CoshIntegral[7*(a/b + ArcCosh[ 
c*x])] + 5*Sinh[a/b]*SinhIntegral[a/b + ArcCosh[c*x]] - 9*Sinh[(3*a)/b]*Si 
nhIntegral[3*(a/b + ArcCosh[c*x])] + 5*Sinh[(5*a)/b]*SinhIntegral[5*(a/b + 
 ArcCosh[c*x])] - Sinh[(7*a)/b]*SinhIntegral[7*(a/b + ArcCosh[c*x])]))/(64 
*c^2*Sqrt[(-1 + c*x)/(1 + c*x)]*(b + b*c*x))
 

3.3.86.3 Rubi [A] (verified)

Time = 0.64 (sec) , antiderivative size = 223, normalized size of antiderivative = 0.56, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {6367, 5971, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {x \left (1-c^2 x^2\right )^{5/2}}{a+b \text {arccosh}(c x)} \, dx\)

\(\Big \downarrow \) 6367

\(\displaystyle \frac {\sqrt {1-c x} \int \frac {\cosh \left (\frac {a}{b}-\frac {a+b \text {arccosh}(c x)}{b}\right ) \sinh ^6\left (\frac {a}{b}-\frac {a+b \text {arccosh}(c x)}{b}\right )}{a+b \text {arccosh}(c x)}d(a+b \text {arccosh}(c x))}{b c^2 \sqrt {c x-1}}\)

\(\Big \downarrow \) 5971

\(\displaystyle \frac {\sqrt {1-c x} \int \left (\frac {\cosh \left (\frac {7 a}{b}-\frac {7 (a+b \text {arccosh}(c x))}{b}\right )}{64 (a+b \text {arccosh}(c x))}-\frac {5 \cosh \left (\frac {5 a}{b}-\frac {5 (a+b \text {arccosh}(c x))}{b}\right )}{64 (a+b \text {arccosh}(c x))}+\frac {9 \cosh \left (\frac {3 a}{b}-\frac {3 (a+b \text {arccosh}(c x))}{b}\right )}{64 (a+b \text {arccosh}(c x))}-\frac {5 \cosh \left (\frac {a}{b}-\frac {a+b \text {arccosh}(c x)}{b}\right )}{64 (a+b \text {arccosh}(c x))}\right )d(a+b \text {arccosh}(c x))}{b c^2 \sqrt {c x-1}}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {\sqrt {1-c x} \left (-\frac {5}{64} \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a+b \text {arccosh}(c x)}{b}\right )+\frac {9}{64} \cosh \left (\frac {3 a}{b}\right ) \text {Chi}\left (\frac {3 (a+b \text {arccosh}(c x))}{b}\right )-\frac {5}{64} \cosh \left (\frac {5 a}{b}\right ) \text {Chi}\left (\frac {5 (a+b \text {arccosh}(c x))}{b}\right )+\frac {1}{64} \cosh \left (\frac {7 a}{b}\right ) \text {Chi}\left (\frac {7 (a+b \text {arccosh}(c x))}{b}\right )+\frac {5}{64} \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a+b \text {arccosh}(c x)}{b}\right )-\frac {9}{64} \sinh \left (\frac {3 a}{b}\right ) \text {Shi}\left (\frac {3 (a+b \text {arccosh}(c x))}{b}\right )+\frac {5}{64} \sinh \left (\frac {5 a}{b}\right ) \text {Shi}\left (\frac {5 (a+b \text {arccosh}(c x))}{b}\right )-\frac {1}{64} \sinh \left (\frac {7 a}{b}\right ) \text {Shi}\left (\frac {7 (a+b \text {arccosh}(c x))}{b}\right )\right )}{b c^2 \sqrt {c x-1}}\)

input

Int[(x*(1 - c^2*x^2)^(5/2))/(a + b*ArcCosh[c*x]),x]
 

output

(Sqrt[1 - c*x]*((-5*Cosh[a/b]*CoshIntegral[(a + b*ArcCosh[c*x])/b])/64 + ( 
9*Cosh[(3*a)/b]*CoshIntegral[(3*(a + b*ArcCosh[c*x]))/b])/64 - (5*Cosh[(5* 
a)/b]*CoshIntegral[(5*(a + b*ArcCosh[c*x]))/b])/64 + (Cosh[(7*a)/b]*CoshIn 
tegral[(7*(a + b*ArcCosh[c*x]))/b])/64 + (5*Sinh[a/b]*SinhIntegral[(a + b* 
ArcCosh[c*x])/b])/64 - (9*Sinh[(3*a)/b]*SinhIntegral[(3*(a + b*ArcCosh[c*x 
]))/b])/64 + (5*Sinh[(5*a)/b]*SinhIntegral[(5*(a + b*ArcCosh[c*x]))/b])/64 
 - (Sinh[(7*a)/b]*SinhIntegral[(7*(a + b*ArcCosh[c*x]))/b])/64))/(b*c^2*Sq 
rt[-1 + c*x])
 

3.3.86.3.1 Defintions of rubi rules used

rule 2009

Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 5971

Int[Cosh[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sinh[(a_.) + 
(b_.)*(x_)]^(n_.), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sinh[a + 
b*x]^n*Cosh[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] & 
& IGtQ[p, 0]
 

rule 6367

Int[((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_.)*((d_) + (e_.)*(x_) 
^2)^(p_.), x_Symbol] :> Simp[(1/(b*c^(m + 1)))*Simp[(d + e*x^2)^p/((1 + c*x 
)^p*(-1 + c*x)^p)]   Subst[Int[x^n*Cosh[-a/b + x/b]^m*Sinh[-a/b + x/b]^(2*p 
 + 1), x], x, a + b*ArcCosh[c*x]], x] /; FreeQ[{a, b, c, d, e, n}, x] && Eq 
Q[c^2*d + e, 0] && IGtQ[2*p + 2, 0] && IGtQ[m, 0]
 

3.3.86.4 Maple [A] (verified)

Time = 0.51 (sec) , antiderivative size = 318, normalized size of antiderivative = 0.80

method	result	size
default	\(\frac {\sqrt {-c^{2} x^{2}+1}\, \left (-\sqrt {c x -1}\, \sqrt {c x +1}\, c x +c^{2} x^{2}-1\right ) \left (\operatorname {Ei}_{1}\left (7 \,\operatorname {arccosh}\left (c x \right )+\frac {7 a}{b}\right ) {\mathrm e}^{\frac {b \,\operatorname {arccosh}\left (c x \right )+7 a}{b}}+\operatorname {Ei}_{1}\left (-7 \,\operatorname {arccosh}\left (c x \right )-\frac {7 a}{b}\right ) {\mathrm e}^{-\frac {-b \,\operatorname {arccosh}\left (c x \right )+7 a}{b}}-5 \,\operatorname {Ei}_{1}\left (5 \,\operatorname {arccosh}\left (c x \right )+\frac {5 a}{b}\right ) {\mathrm e}^{\frac {b \,\operatorname {arccosh}\left (c x \right )+5 a}{b}}+9 \,\operatorname {Ei}_{1}\left (3 \,\operatorname {arccosh}\left (c x \right )+\frac {3 a}{b}\right ) {\mathrm e}^{\frac {b \,\operatorname {arccosh}\left (c x \right )+3 a}{b}}-5 \,\operatorname {Ei}_{1}\left (\operatorname {arccosh}\left (c x \right )+\frac {a}{b}\right ) {\mathrm e}^{\frac {a +b \,\operatorname {arccosh}\left (c x \right )}{b}}-5 \,\operatorname {Ei}_{1}\left (-\operatorname {arccosh}\left (c x \right )-\frac {a}{b}\right ) {\mathrm e}^{-\frac {-b \,\operatorname {arccosh}\left (c x \right )+a}{b}}+9 \,\operatorname {Ei}_{1}\left (-3 \,\operatorname {arccosh}\left (c x \right )-\frac {3 a}{b}\right ) {\mathrm e}^{-\frac {-b \,\operatorname {arccosh}\left (c x \right )+3 a}{b}}-5 \,\operatorname {Ei}_{1}\left (-5 \,\operatorname {arccosh}\left (c x \right )-\frac {5 a}{b}\right ) {\mathrm e}^{-\frac {-b \,\operatorname {arccosh}\left (c x \right )+5 a}{b}}\right )}{128 \left (c x +1\right ) c^{2} \left (c x -1\right ) b}\)	\(318\)

input

int(x*(-c^2*x^2+1)^(5/2)/(a+b*arccosh(c*x)),x,method=_RETURNVERBOSE)
 

output

1/128*(-c^2*x^2+1)^(1/2)*(-(c*x-1)^(1/2)*(c*x+1)^(1/2)*c*x+c^2*x^2-1)*(Ei( 
1,7*arccosh(c*x)+7*a/b)*exp((b*arccosh(c*x)+7*a)/b)+Ei(1,-7*arccosh(c*x)-7 
*a/b)*exp(-(-b*arccosh(c*x)+7*a)/b)-5*Ei(1,5*arccosh(c*x)+5*a/b)*exp((b*ar 
ccosh(c*x)+5*a)/b)+9*Ei(1,3*arccosh(c*x)+3*a/b)*exp((b*arccosh(c*x)+3*a)/b 
)-5*Ei(1,arccosh(c*x)+a/b)*exp((a+b*arccosh(c*x))/b)-5*Ei(1,-arccosh(c*x)- 
a/b)*exp(-(-b*arccosh(c*x)+a)/b)+9*Ei(1,-3*arccosh(c*x)-3*a/b)*exp(-(-b*ar 
ccosh(c*x)+3*a)/b)-5*Ei(1,-5*arccosh(c*x)-5*a/b)*exp(-(-b*arccosh(c*x)+5*a 
)/b))/(c*x+1)/c^2/(c*x-1)/b
 

3.3.86.5 Fricas [F]

\[ \int \frac {x \left (1-c^2 x^2\right )^{5/2}}{a+b \text {arccosh}(c x)} \, dx=\int { \frac {{\left (-c^{2} x^{2} + 1\right )}^{\frac {5}{2}} x}{b \operatorname {arcosh}\left (c x\right ) + a} \,d x } \]

input

integrate(x*(-c^2*x^2+1)^(5/2)/(a+b*arccosh(c*x)),x, algorithm="fricas")
 

output

integral((c^4*x^5 - 2*c^2*x^3 + x)*sqrt(-c^2*x^2 + 1)/(b*arccosh(c*x) + a) 
, x)
 

3.3.86.6 Sympy [F(-1)]

Timed out. \[ \int \frac {x \left (1-c^2 x^2\right )^{5/2}}{a+b \text {arccosh}(c x)} \, dx=\text {Timed out} \]

input

integrate(x*(-c**2*x**2+1)**(5/2)/(a+b*acosh(c*x)),x)
 

output

Timed out
 

3.3.86.7 Maxima [F]

\[ \int \frac {x \left (1-c^2 x^2\right )^{5/2}}{a+b \text {arccosh}(c x)} \, dx=\int { \frac {{\left (-c^{2} x^{2} + 1\right )}^{\frac {5}{2}} x}{b \operatorname {arcosh}\left (c x\right ) + a} \,d x } \]

input

integrate(x*(-c^2*x^2+1)^(5/2)/(a+b*arccosh(c*x)),x, algorithm="maxima")
 

output

integrate((-c^2*x^2 + 1)^(5/2)*x/(b*arccosh(c*x) + a), x)
 

3.3.86.8 Giac [F]

\[ \int \frac {x \left (1-c^2 x^2\right )^{5/2}}{a+b \text {arccosh}(c x)} \, dx=\int { \frac {{\left (-c^{2} x^{2} + 1\right )}^{\frac {5}{2}} x}{b \operatorname {arcosh}\left (c x\right ) + a} \,d x } \]

input

integrate(x*(-c^2*x^2+1)^(5/2)/(a+b*arccosh(c*x)),x, algorithm="giac")
 

output

integrate((-c^2*x^2 + 1)^(5/2)*x/(b*arccosh(c*x) + a), x)
 

3.3.86.9 Mupad [F(-1)]

Timed out. \[ \int \frac {x \left (1-c^2 x^2\right )^{5/2}}{a+b \text {arccosh}(c x)} \, dx=\int \frac {x\,{\left (1-c^2\,x^2\right )}^{5/2}}{a+b\,\mathrm {acosh}\left (c\,x\right )} \,d x \]

input

int((x*(1 - c^2*x^2)^(5/2))/(a + b*acosh(c*x)),x)
 

output

int((x*(1 - c^2*x^2)^(5/2))/(a + b*acosh(c*x)), x)